To calculate the total resistance in parallel, we can use the formula:
1/Rtotal = 1/R1 + 1/R2
Substituting the values, we have:
1/Rtotal = 1/5k + 1/3k
Simplifying, we get:
1/Rtotal = (3k + 5k) / (5k * 3k)
1/Rtotal = 8k / 15k
Rtotal = 15k / 8k
Rtotal = 1.875k ohms
Therefore, the total resistance when both potentiometers are connected in parallel is approximately 1.875k oh